13=1/x(2x^2+15)

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Solution for 13=1/x(2x^2+15) equation: 



13=1/x(2x^2+15)

We move all terms to the left:

13-(1/x(2x^2+15))=0



Domain of the equation: x(2x^2+15))!=0

x∈R



We multiply all the terms by the denominator


-(1+13*x(2x^2+15))=0



We calculate terms in parentheses: -(1+13*x(2x^2+15)), so:

1+13*x(2x^2+15)

determiningTheFunctionDomain
13*x(2x^2+15)+1

Wy multiply elements

13x(2+1

Back to the equation:

-(13x(2+1)



We add all the numbers together, and all the variables

-(13x3=0

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